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Example
Chosen measurement -50 ... +150 °C → 200 K span
range: 1 % from 200 K span = 2 K
Set minimum temperature -50 °C + 2 K = -48 °C
on the PT 100 simulator and calibrate the signal conditioner out-
put signal to 0.100 V using the null potentiometer.
Mean temperature = (ϑ
max
+ ϑ
min
)/2
= (150 °C + (-50 °C))/2
= 50 °C
Set the 50 °C value on the PT 100 simulator
Then determine ∆U: ∆U = measured value from measuring
instrument - 5.000 V
→ ∆U = 4.970 V - 5.000 V
= -0.030 V
Then calibrate the output signal to (5.000 V - ∆U) using the span
potentiometer i.e. here an example.
"5.000 V - (-0.030 V) = 5.030 V"
Then set the maximum temperature on a PT 100 simulator and
calibrate the output signal to 10.000 V using the lin potentiome-
ter.
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